# If an alternating current of i(t) = 2sin(3/2*pi*t) A flows from a voltage source of v(t) = 5.0V , fi

If an alternating current of i(t) = 2sin(3/2*pi*t) A flows from a voltage source of v(t) = 5.0V , find the energy used in the first second.

I did i(t) = 2sin((3/2)*pi) = -2. Then i*v*t = (-2)(5)(1) = -10, but thats not correct.

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